10X^2+60x+10=0

Solution for 10X^2+60x+10=0 equation:

10X^2+60X+10=0

a = 10; b = 60; c = +10;
Δ = b2-4ac
Δ = 602-4·10·10
Δ = 3200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3200}=\sqrt{1600*2}=\sqrt{1600}*\sqrt{2}=40\sqrt{2}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-40\sqrt{2}}{2*10}=\frac{-60-40\sqrt{2}}{20}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+40\sqrt{2}}{2*10}=\frac{-60+40\sqrt{2}}{20}
$